# The height of the rhombus drawn from the top of the obtuse angle bisects the side of the rhombus.

**The height of the rhombus drawn from the top of the obtuse angle bisects the side of the rhombus. Determine the corners of the diamond.**

Since the CH height divides the AD side in half, it is also the median of the ACD triangle.

If the median coincides with the height of the triangle, then this triangle is isosceles, AC = DC.

Since all sides of a rhombus are equal, then AD = CD, and therefore CD = AC and triangle ACD is equilateral.

In an equilateral triangle, all angles are 60, the angle ACD = CDA CAD = 60.

The diagonals of the rhombus divide the angles at the vertices in half, then the angle BAD / 2 = CAD.

Angle BAD = 2 * CAD = 2 * 60 = 120.

In a rhombus, the opposite angles are equal, then the angle ABC = ADC = 60, the angle BAD = BCD = 120.

Answer: The angles of the rhombus are 60 and 120.