Let the value of the angle CAB = 2 * X0, then, by condition, the value of the angle ACB = 3 * X0, and the angle ABC = 4 * X0.
The sum of the inner angles of the triangle is 180, then (2 * X + 3 * X + 4 * X) = 180.
9 * X = 180.
X = 180/9 = 20.
Then the angle CAB = 2 * 20 = 40, angle ACB = 3 * 30 = 60, angle ABC = 4 * 20 = 80.
Answer: The angles of the triangle are 40, 60, 80.
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