The intercity bus traveled 100 km of its route in 1.5 hours, and the remaining 40 km

The intercity bus traveled 100 km of its route in 1.5 hours, and the remaining 40 km in 15 minutes. What was the average speed of its movement?

Task data: S1 (length of the first part of the route) = 100 km; t1 (time spent on the first part of the route) = 1.5 hours; S2 (length of the rest of the route) = 40 km; t2 (time taken for the remainder of the route) = 15 minutes (0.25 hours).

The average speed of an intercity bus is calculated by the formula: Vav. = (S1 + S2) / (t1 + t2).

Let’s calculate: Vav. = (100 + 40) / (1.5 + 0.25) = 140 / 1.75 = 80 km / h.

Answer: the intercity bus on its route moved at an average speed of 80 km / h.