The intercity bus traveled 100 km of its route in 1.5 hours, and the remaining 40 km in 15 minutes. What was the average speed of its movement?
Task data: S1 (length of the first part of the route) = 100 km; t1 (time spent on the first part of the route) = 1.5 hours; S2 (length of the rest of the route) = 40 km; t2 (time taken for the remainder of the route) = 15 minutes (0.25 hours).
The average speed of an intercity bus is calculated by the formula: Vav. = (S1 + S2) / (t1 + t2).
Let’s calculate: Vav. = (100 + 40) / (1.5 + 0.25) = 140 / 1.75 = 80 km / h.
Answer: the intercity bus on its route moved at an average speed of 80 km / h.
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