# The length of a rectangular parallelepiped is 40% longer than its width, and its width is 5 times less than its height.

The length of a rectangular parallelepiped is 40% longer than its width, and its width is 5 times less than its height. What is the total surface area of a parallelepiped if its volume is 56 dm3?

Let’s designate the width of the parallelepiped as “x” dm, then taking into account the condition of the problem, its length will be “x + 0.4x” dm, and the height will be equal to “5x” dm.

Let’s make an equation taking into account that the volume of this parallelepiped is 56 dm³.

x * 1.4x * 5x = 56;

1.4x² * 5x = 56;

7x³ = 56;

x³ = 56/7;

x³ = 8;

x = ³√8 = 2 dm width.

1.4 * 2 = 2.8 dm length.

5 * 2 = 10 dm height.

Let’s calculate the total surface area:

S = 2 * (a * b + b * c + a * c) = 2 * (2.8 * 2 + 2 * 10 + 2.8 * 10) = 2 * (5.6 + 20 + 28) = 107.2 dm². One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.