# The length of the rectangle is 13 cm, and the area is 65 cm squared. Find the area of a rectangle

**The length of the rectangle is 13 cm, and the area is 65 cm squared. Find the area of a rectangle that is 4 cm long and 3 times wider than the given one. Find the perimeter of 2 rectangles.**

First, we find out what the width of the first rectangle is equal to, if its area and length are known by the problem statement:

S = a * b, where a is the length, b is the width.

b = S / a = 65/13 = 5 cm.

Now let’s determine what the length of the second rectangle is equal to:

13 + 4 = 17 cm.

Next, we find the width of the second rectangle:

3 * 5 = 15 cm.

It remains to find out what the perimeter of the second rectangle is, if its length and width are known:

P = 2a + 2b, where a is the length, b is the width.

P = 2 * 15 + 2 * 17 = 30 + 34 = 64 cm.

Answer: The perimeter of rectangle 2 is 64 centimeters.