# The length of the rectangle is 2 cm more than the width, if you increase the length by 4 cm

**The length of the rectangle is 2 cm more than the width, if you increase the length by 4 cm, then the perimeter will become 48 cm, which is what the sides of the rectangle are equal to.**

Let the width of the rectangle be x cm, then the length of the rectangle is (x + 2) cm.If the length of the rectangle is increased by 4 cm, then it will become (x + 2) + 4 = x + 6 (cm). According to the condition of the problem, it is known that one hundred after increasing the length by 4 cm, the perimeter of the rectangle (the perimeter is the sum of the lengths of all sides P = 2 (a + b)) will be equal to 2 (x + (x + 6)) cm or 48 cm. equation and solve it.

2 (x + (x + 6)) = 48;

2 (x + x + 6) = 48;

2 (2x + 6) = 48;

4x + 12 = 48;

4x = 48 – 12;

4x = 36;

x = 36: 4;

x = 9 (cm) – width;

x + 2 = 9 + 2 = 11 (cm) – length.

Answer. 9 cm, 11 cm.