# The length of the rectangle is 30% longer than the width, and its perimeter is 36.8 m. Find the area of the rectangle.

March 31, 2021 | education

| Let the width of the rectangle be x meters, then its length is x + 3x / 10. Since the perimeter of the rectangle is 36.8 meters, we will compose the equation:

x + x + 3x / 10 = 36.8

2x + 3x / 10 = 36.8 – reduce to a common denominator 10

20x + 3x = 368

23x = 368

x = 368/23

x = 16 – the width of the rectangle

16 + 3 * 16/10 = 16 + 4.8 = 20.8 (m) – the length of the rectangle

The area of the rectangle is sought by the formula – S = a * b (where a is the length, b is the width, and S is the area).

20.8m * 16m = 332.8 (m ^ 2) – area of a rectangle

1 m ^ 2 = 100 dm ^ 2

332.8 m ^ 2 = 33280 dm ^ 2.

Answer. The area of the rectangle is 33,280 dm ^ 2.

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