# The length of the rectangle is 30% longer than the width, and its perimeter is 36.8 m. Find the area of the rectangle.

Let the width of the rectangle be x meters, then its length is x + 3x / 10. Since the perimeter of the rectangle is 36.8 meters, we will compose the equation:
x + x + 3x / 10 = 36.8
2x + 3x / 10 = 36.8 – reduce to a common denominator 10
20x + 3x = 368
23x = 368
x = 368/23
x = 16 – the width of the rectangle
16 + 3 * 16/10 = 16 + 4.8 = 20.8 (m) – the length of the rectangle
The area of the rectangle is sought by the formula – S = a * b (where a is the length, b is the width, and S is the area).
20.8m * 16m = 332.8 (m ^ 2) – area of a rectangle
1 m ^ 2 = 100 dm ^ 2
332.8 m ^ 2 = 33280 dm ^ 2.
Answer. The area of the rectangle is 33,280 dm ^ 2. One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.