The length of the rectangle is 9 cm longer than the side of the square, and the width is 9 cm less

The length of the rectangle is 9 cm longer than the side of the square, and the width is 9 cm less. Which of the figures has a larger area and by how much?

1. Let x be the length of the side of the square.

2. Then x + 9 is the length of the rectangle.

3.x – 9 – the width of the rectangle.

4. Find the area of the square.

x * x = x ^ 2.

5. Find the area of the rectangle.

(x + 9) * (x – 9) = x ^ 2 – 81

6.x ^ 2> x ^ 2 – 81 by 81

Answer: the area of the square is 81 cm2 larger than the area of the rectangle.