# The length of the rectangular parallelepiped is 8 m, the width is 6 meters and the height is 12 m

September 14, 2021 | education

| **The length of the rectangular parallelepiped is 8 m, the width is 6 meters and the height is 12 m. Find the sum of the areas of the largest and smallest faces of this parallelepiped.**

It is necessary to find the sum of the areas of the largest and smallest faces of a parallelepiped, which is 8 meters long, 6 meters wide, and 12 meters high.

The faces of a rectangular parallelepiped are rectangles whose areas are equal to the product of two dimensions S = a * b. The smallest face of a rectangular parallelepiped has the smallest linear dimensions of 6 m and 8 m. The largest face of a rectangular parallelepiped is a rectangle with sides of 12 m and 8 m.

Let’s make the sum of the areas:

6 * 8 + 12 * 8 = 144 (m ^ 2)

Answer: 144 m ^ 2.

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