The length of the rectangular parallelepiped is 8 m, the width is 6 meters and the height is 12 m

The length of the rectangular parallelepiped is 8 m, the width is 6 meters and the height is 12 m. Find the sum of the areas of the largest and smallest faces of this parallelepiped.

It is necessary to find the sum of the areas of the largest and smallest faces of a parallelepiped, which is 8 meters long, 6 meters wide, and 12 meters high.

The faces of a rectangular parallelepiped are rectangles whose areas are equal to the product of two dimensions S = a * b. The smallest face of a rectangular parallelepiped has the smallest linear dimensions of 6 m and 8 m. The largest face of a rectangular parallelepiped is a rectangle with sides of 12 m and 8 m.

Let’s make the sum of the areas:

6 * 8 + 12 * 8 = 144 (m ^ 2)

Answer: 144 m ^ 2.




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