The lever is in balance under the action of two forces. The first force of 4N has a shoulder of 15 cm.

The lever is in balance under the action of two forces. The first force of 4N has a shoulder of 15 cm. Determine what the second force is equal to if its shoulder is 10 cm.

To keep the lever in balance, the moments of the forces acting on it must coincide.

The moment of force is the product of the force by the length of the arm to which this force is applied:

M = F * l.

If M1 = M2 then F1 * l1 = F2 * l2.

F2 = (F1 * l1) / l2 = (4 * 0.15) / 0.10 = 6 N.



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