The lift rises with an acceleration of 1m / s2, the acceleration vector is directed vertically upward. a body with a mass of 1 kg rests in the elevator. what is the body weight?
a = 1 m / s2.
g = 9.8 m / s2.
m = 1 kg.
When the lift moves, 2 forces act on the body that is in it: the gravity force m * g, directed vertically downward, and the reaction force of the floor of the lift N, directed vertically upward. The body moves with acceleration a, which is directed vertically upward.
2 Newton’s law will have the form: m * a = N – m * g.
Let us express the force of the sex reaction to the body: N = m * a + m * g = m * (a + g).
According to Newton’s 3 law, the force N with which the floor presses on the body is equal to the force P with which the body presses on the floor, that is, the weight: N = P.
P = m * (a + g).
P = 1 kg * (1 m / s2 + 9.8 m / s2) = 10.8 N.
Answer: the body weight during the movement of the elevator is P = 10.8 N.
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