The lifting capacity of the elevator is 3 tons. How many sheets of iron can be loaded into the elevator

The lifting capacity of the elevator is 3 tons. How many sheets of iron can be loaded into the elevator if each sheet is 3 meters long, 60 cm wide and 4 millimeters thick.

1) The volume of one sheet (we assume that the sheet is a rectangular parallelepiped):

V = a * b * c, where a is the length (a = 3 m), b is the width (b = 0.6 m), c is the thickness (c = 0.004 m).

V = a * b * c = 3 * 0.6 * 0.004 = 0.0072 m3.

2) Weight of one sheet:

m = ρ * V, where ρ is the density of iron (ρ = 7800 kg / m³).

m = ρ * V = 7800 * 0.0072 = 56.16 kg.

3) Maximum number of sheets:

n = m1 / m, where m1 is the lifting capacity of the elevator (m1 = 3 t = 3000 kg).

n = m1 / m = 3000 / 56.16 = 53.42 = 53 sheets.



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