The manufacture of an iron container requires 3 kg 330 g of iron, and the manufacture of a lid for this container requires

The manufacture of an iron container requires 3 kg 330 g of iron, and the manufacture of a lid for this container requires three times less metal mass. How many kg of metal is needed to make 4 such containers.

1) Let’s calculate how much iron is required to make a lid for a container:

3 kg 300 g: 3 = 3 kg: 3 + 300 g: 3 = 1 kg + 100 g = 1 kg 100 g.

2) Find the amount of iron that is required to make one container and a lid for it:

3 kg 300 g + 1 kg 100 g = (3 kg + 1 kg) + (300 g + 100 g) = 4 kg + 400 g = 4 kg 400 g.

3) Find out how much iron is required to make four containers with lids:

4 kg 400 g * 4 = 4 kg * 4 + 400 g * 4 = 16 kg + 1600 g = 16 kg + 1 kg + 600 g = 17 kg 600 g = 17.6 kg.

Answer: 17.6 kg.