The mass of 2 tin ingots and 5 lead ingots is 33 kg, and the mass of 6 tin ingots and 2 lead

The mass of 2 tin ingots and 5 lead ingots is 33 kg, and the mass of 6 tin ingots and 2 lead ingots is 34 kg. What is the mass of one tin ingot and what is the mass of one lead ingot?

Let’s solve the problem with a system of equations:
Let the ingot of tin be x;
and an ingot of lead is y;
Then we get the following system of equations:
2x + 5y = 33;
6x + 2y = 34;
And we will solve it using the substitution method:
2x = 33 – 5y;
x = (33 – 5y) / 2 = 16, 5 – 2, 5y;
6 * (16, 5 – 2, 5y) + 2y = 34;
99 – 15y + 2y = 34;
– 13y = 34 – 99;
13y = 65;
y = 65/13 = 5;
x = 16, 5 – 2, 5 * 5 = 16, 5 – 12, 5 = 4.
Thus, the weight of the tin ingot was 4 kg, and the weight of the lead ingot was 5 kg.