1.4Al + 3O2 = 2Al2O3 – compounds, aluminum oxide is released;
Calculations of the molar masses of substances:
M (O2) = 32 g / mol;
M (Al2O3) = 101.8 g / mol.
1 mol of gas at normal level – 22.4 liters;
X mol (O2) – 134.4 liters from here, X mol (O2) = 1 * 134.4 / 22.4 = 6 mol.
6 mol (О2) – X mol (Al2O3);
-3 mol -2 mol from here, X mol (Al2O3) = 6 * 2/3 = 4 mol.
Find the mass of the product:
m (Al2O3) = Y * M = 4 * 102.8 = 407.2 g
Answer: Received aluminum oxide weighing 407.2 g
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