The mass of magnesium oxide that can be obtained by burning 4.8 g of magnesium in an excess of oxygen

The mass of magnesium oxide that can be obtained by burning 4.8 g of magnesium in an excess of oxygen in accordance with the reaction equation (2Mg + O2 = 2MgO).

Magnesium is oxidized very intensively by oxygen. This reaction is described by the following equation:

Mg + ½ O2 = MgO;

During oxidation, one oxygen atom is attached to the magnesium atom. In this case, one molecule of magnesium oxide is synthesized.

Let’s determine the molar amount of magnesium.

To do this, divide the available weight of magnesium by the weight of 1 mole of this substance.

M Mg = 24 grams / mol; N Mg = 4.8 / 24 = 0.2 mol;

When this reaction proceeds, the same amount of magnesium oxide will be synthesized.

Let’s calculate its weight.

To do this, we multiply the amount of the substance by the weight of 1 mole of the substance.

M MgO = 24 + 16 = 40 grams / mol; m MgO = 0.2 x 40 = 8 grams;



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