The mass of nitrogen oxide obtained during the catalytic oxidation of 5 liters of ammonia.

Let’s implement the solution:

In accordance with the condition of the problem, we compose the equation of the process:
V = 5 L X g -?

4NH3 + 5O2 = 4NO + 6H2O – oxidation, nitrogen oxide was obtained (2);

Calculations:
M (NH3) = 17 g / mol;

M (NO) = 30 g / mol.

Proportion:
1 mol of gas at normal level – 22.4 liters;

X mol (NH3) -5 L from here, X mol (NH3) = 1 * 5 / 22.4 = 0.2 mol.

Y (NO) = 0.2 mol since the amount of these substances is 4 mol.

Find the mass of the oxide:
m (NO) = Y * M = 0.2 * 30 = 6 g

Answer: the mass of nitric oxide is 6 g



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