The mass of sodium chloride required for the preparation of 5 liters of physiological solution

The mass of sodium chloride required for the preparation of 5 liters of physiological solution (p = 1.01 g / cm3) with a mass fraction of salt of 0.9% is equal to ..

Let’s calculate the weight of the dissolved salt.

M salt = 5000 x 1.01 x 0.009 = 45.45 grams;

Similarly, we find the weight of the solvent (water).

(In the calculations, we take the density of water equal to 1 gram / ml).

M water (solvent) = 5000 x 1.01 x 0.991 = 5004.55 grams = 5004.55 ml;

Let’s check. To do this, we add the masses of the components of the solution and get the mass of the solution in question.

45.45 + 5004.55 = 5050;