The maximum efficiency of an ideal heat engine is 25%. determine the temperature of the refrigerator. if the heater temperature is 400k.
These tasks: η (maximum efficiency of a given ideal heat engine) = 25% or 0.25; Тн (heater temperature) = 400 K.
To determine the temperature of the refrigerator of a given ideal heat engine, we will use the formula: η = 1 – Тх / Тн, whence Тх = (1 – η) * Тн.
Let’s calculate: Tx = (1 – 0.25) * 400 = 300 K.
Answer: A given ideal heat engine has a refrigerator temperature of 300 K.
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