The midline of an isosceles triangle, parallel to the base, is 4cm, and its perimeter is 28cm. Find the side of the triangle.

You are given an isosceles triangle ABC with base AC; AB = BC;

The middle line DE is equal to half of the base AC, which means that the base

AC = 2 * DE = 2 * 4 = 8 cm;

The perimeter of the triangle is AB + BC + AC = 28; AB + BC = 28 – 8 = 20;

Since AB = BC, the side is 20/2 = 10 cm.



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