The minibus moved 1 km under the action of a 2kN traction force.

The minibus moved 1 km under the action of a 2kN traction force. Determine the distance traveled by the minibus under the force of 1250N. The performed mesanic work is the same in both cases.

We express the mechanical work of a minibus by the formula: A = F * S.
Since in both cases the mechanical work is equal, then
F1 * S1 = F2 * S2, where F1 is the first traction force of the minibus (F1 = 2 kN = 2 * 10 ^ 3 N), F2 is the second traction force of the minibus (F2 = 1250 N), S1 is the first movement of the minibus (S = 1 km = 1 * 10 ^ 3 m), S1 – the second movement of the minibus.
Let’s calculate the second movement of the minibus:
S2 = F1 * S1 / F2 = (2 * 10 ^ 3 * 1 * 10 ^ 3) / 1250 = 1600 m.
Answer. The second movement of the minibus is 1600 m.