The modem transmits information at a rate of 1440 bps. The page is 1800 bytes. Determine how long

The modem transmits information at a rate of 1440 bps. The page is 1800 bytes. Determine how long it will take to transfer three pages.

First, we find the total information volume of three pages.

To do this, we multiply the known volume of one page by their number.

1800 * 3 = 5400 bytes.

We translate the information volume into bits.

Since 1 byte contains 8 bits, we get:

5400 * 8 = 43200 bits.

Find the file transfer time.

To do this, we divide the total information volume of the file by the modem transmission rate, which is 1440 bit / s.

Will:

43200/1440 = 30 seconds.

30 seconds = 30/60 = 0.5 minutes.

Answer:

It will take 0.5 minutes.



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