The molecular weight of some monosaccharide is 180, the carbon content is 40%,

The molecular weight of some monosaccharide is 180, the carbon content is 40%, hydrogen is 7%, oxygen is 53%. Establish the molecular formula of a substance, name it.

m (C) = n * M = 180 g / mol * 0.4 mol = 72 g.
m (H) = n * M = 180 g / mol * 0.07 mol = 12 g.
m (O) = n * M = 180 g / mol * 0.53 mol = 95 g.

n (C) = m / M = 72g / (12g / mol) = 6 atoms.
n (H) = m / M = 12g / (1g / mol) = 12 atoms.
n (O) = m / M = 95g / (16g / mol) = 6 atoms.

Answer: С6H12O6 (this is glucose or fructose).



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