The moment of force of the lever is 15N * m. What is the arm of the lever if a force of 30n is applied to it?

Task data: M (moment of force of a given lever) = 15 N * m; F (force applied to the shoulder) = 30 N.

The leverage of a given leverage can be expressed from the formula: M = F * x, whence x = M / F.

Let’s perform the calculation: x = 15/30 = 0.5 m (50 cm).

Answer: The arm of the given lever is 50 centimeters long.

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