The monoatomic ideal gas, at a pressure of 300 kPa, expanded isobarically from 2 m3 to 7 MJ. Determine the work done by the gas.
Let us give the values from given in the SI system:
p = 300 kPa = 300000 Pa.
The work done by the gas during expansion is equal to:
A = p * ∆V
∆V = V2-V1
Let’s substitute in expressions for work:
A = p * ∆V = p * (V2-V1)
Let’s substitute the numbers and define the work of the gas:
A = p * (V2-V1) = 300000 * (7-2) = 1500000 J.
Answer: the work of the gas is 1,500,000 J or 1.5 MJ.
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