The nitrogen vapor density of cycloparaffin is 2.5. Carbon content – 85.71%

The nitrogen vapor density of cycloparaffin is 2.5. Carbon content – 85.71%, hydrogen – 14.29%. Establish the formula of the substance. (C5H10.)

To solve, we write down data on the condition of the problem:
1. Given: CnH2n – cycloparaffin;
D (N2) = 2.5;
M (N2) = 28 g / mol;
W (C) = 85.17%
W (H) = 14.29%
ShNu -?
2. Calculation of the molar mass of organic matter:
M (CxHy) = M (N2) * D (N2) = 28 * 2.5 = 70 g / mol.
3. Determine the number of moles:
Y (C) = m / M = 85.71 / 12 = 7.14;
Y (H) = 14.29 / 1 = 14.29.
5. The ratio X: Y = 7.14: 14.29 = 1: 2 (divide by the smallest number).
6. CnH2n – general formula;
CnH2n = 70;
12n + 2 = 70;
n = 5.6;
Molecular Formula: C5H10;
Checking: M (C5H10) = 70 g / mol.
Answer: C5H10 – cyclopentane.



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