The oscillating circuit emits electromagnetic waves with a frequency of 6 MHz. What is their wavelength?

Given:

v = 6 Megahertz – frequency of electromagnetic waves emitted by the oscillatory circuit;

c = 300,000 kilometers per second = 3 * 10 ^ 8 meters per second – the speed of propagation of electromagnetic waves (constant).

It is required to determine the wavelength L (meter).

Let’s convert the units of measurement of frequency to the SI system:

v = 6 MHz = 6 * 10 ^ 6 Hertz.

Then, the wavelength will be equal to:

c = L * v, hence:

L = c / v = 3 * 10 ^ 8 / (6 * 10 ^ 6) = 3 * 10 ^ 2/6 = 0.5 * 10 ^ 2 = 50 meters.

Answer: the length of the electromagnetic wave is 50 meters.