The outer angle at the apex of an isosceles triangle opposite the base is 106 degrees. Find the angle of the triangle at the base.
1. Since the inner corner at the vertex is adjacent to the outer one, we find its value.
180 – 106 = 74 °.
2. From the condition it is known that the triangle is isosceles, that is, the angles at the base are equal. Let’s calculate what the degree measure of the angle at the base is equal to.
(180 – 74) / 2 = 53 °.
Answer: 53 degrees.
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