# The parachute tester flew 9.8 km without opening the parachute in 150 seconds.

The parachute tester flew 9.8 km without opening the parachute in 150 seconds. Determine how many seconds the air resistance increased the fall time.

Initial data: S (distance traveled by the parachute tester) = 9.8 km, t1 (actual time of fall) = 150 s, the tester’s fall is considered free (V0 = 0 m / s).

Constants: g (acceleration of gravity) = 9.8 m / s ^ 2.

SI system: S = 9.8 km = 9800 m.

The fall time without taking into account air resistance can be calculated from the formula:

S = V0 * t2 + a * t2 ^ 2/2 = 0 + g * t2 ^ 2/2.

t2 ^ 2 = 2S / g; t2 = √ (2S / g) = √ (2 * 9800 / 9.8) ≈ 44.7 s.

Time difference: t = t1 – t2 = 150 – 44.7 = 105.3 s.

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