The parachute tester flew 9.8 km without opening the parachute in 150 seconds. Determine how many seconds the air resistance increased the fall time.
Initial data: S (distance traveled by the parachute tester) = 9.8 km, t1 (actual time of fall) = 150 s, the tester’s fall is considered free (V0 = 0 m / s).
Constants: g (acceleration of gravity) = 9.8 m / s ^ 2.
SI system: S = 9.8 km = 9800 m.
The fall time without taking into account air resistance can be calculated from the formula:
S = V0 * t2 + a * t2 ^ 2/2 = 0 + g * t2 ^ 2/2.
t2 ^ 2 = 2S / g; t2 = √ (2S / g) = √ (2 * 9800 / 9.8) ≈ 44.7 s.
Time difference: t = t1 – t2 = 150 – 44.7 = 105.3 s.
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