The parallelogram area ABCD is 28 cm2. The sides AB and AD are respectively 7 cm and 8 cm.

univerkov | June 30, 2021 | education

The parallelogram area ABCD is 28 cm2. The sides AB and AD are respectively 7 cm and 8 cm. Find the acute angle of the parallelogram.

The area of a parallelogram is equal to the product of the lengths of its sides by the sine of the angle between these sides.

Savsd = AB * AD * SinBAD.

SinBAD = Savsd / AB * AD = 28/7 * 8 = 28/56 = 1/2.

Then the angle BAD = arcsin BAD = arsin (1/2) = 30.

Answer: The acute angle of the parallelogram is 30.

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