The parallelogram area ABCD is 28 cm2. The sides AB and AD are respectively 7 cm and 8 cm. Find the acute angle of the parallelogram.
The area of a parallelogram is equal to the product of the lengths of its sides by the sine of the angle between these sides.
Savsd = AB * AD * SinBAD.
SinBAD = Savsd / AB * AD = 28/7 * 8 = 28/56 = 1/2.
Then the angle BAD = arcsin BAD = arsin (1/2) = 30.
Answer: The acute angle of the parallelogram is 30.
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