The perimeter of the rectangle ABCD is 40 dm, the length of the rectangle is 12 cm, find the width of the rectangle.

A rectangle is a quadrilateral in which all angles are straight, that is, equal to 90 degrees. Opposite sides are equal and parallel. The perimeter of a rectangle is equal to the sum of its four sides, or the sum of its length and width times two. From the condition of the problem, the perimeter of the rectangle is known, and the length of the rectangle is also known. Let’s answer the question of the problem.

Find what the width of the rectangle is.

(40 – 12 * 2) / 2 = (40 – 24) / 2 = 16/2 = 8 centimeters.

Answer: The width of the rectangle is eight centimeters.

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