The perimeter of the rectangle is 28 cm, one of its sides is 2 cm larger than the other. Find the area of this rectangle.

1. Let the smaller side of the rectangle be equal to y, then the large side is equal to 2 + y. By doubling the sum of its sides, we get the perimeter of the rectangle. Let’s solve the composed equation:

2 * (y + 2 + y) = 28,

4y + 4 = 28,

4y = 28 – 4,

4y = 24,

y = 24/4,

y = 6 cm.

2. Find the large side of the rectangle:

2 + 6 = 8 cm.

3. Find the product of the larger and smaller sides of the rectangle, get its area:

Area = 8 cm * 6 cm = 48 cm2.

Answer: the area of the rectangle is 48 cm2.




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