The perimeter of the rectangle is 4m 8dm, one of its sides is 5 times larger than the neighboring one, find the area.

1. Let’s translate the perimeter of the rectangle into cm:
4 m 8 dm = 480 cm.
2. Let the smaller of the adjacent sides be equal to a, then the larger side is equal to 5a. Using the formula for the perimeter of a rectangle, we will compose the equation:
2 * (a + 5a) = 480,
2 * 6a = 480,
12a = 480,
a = 480/12,
a = 40.
3. Find the large adjacent side:
5 * 40 = 200 cm.
4. Find the area of the rectangle by multiplying its length by width:
200 * 40 = 8000 cm2.
Answer: the area of the rectangle is 8000 cm2.

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