The perimeter of the rectangle is 72 cm. What are the length and width of the rectangle if the width

The perimeter of the rectangle is 72 cm. What are the length and width of the rectangle if the width is 3 times less than its length?

From the problem statement, we know that the perimeter of the rectangle is 72 centimeters. We know that the perimeter of a rectangle can be found based on the formula:

P = 2 (a + b)

Where
P is the perimeter of the rectangle;
a – the length of the rectangle;
b is the width of the rectangle.

Then we get that:

2 (a + b) = 72

Also, from the condition, we know that the width is three times less than the length. That is:

a = 3b

Thus, we get a system of equations:

2 (a + b) = 72
a = 3b

Substitute the second equation into the first:

2 (3b + b) = 72
b (3 + 1) = 72/2
4b = 36
b = 9 centimeters

Then the length is:

a = 3b = 3 * 9 = 27