# The perimeter of the rectangle is 72 cm. What are the length and width of the rectangle if the width

**The perimeter of the rectangle is 72 cm. What are the length and width of the rectangle if the width is 3 times less than its length?**

From the problem statement, we know that the perimeter of the rectangle is 72 centimeters. We know that the perimeter of a rectangle can be found based on the formula:

P = 2 (a + b)

Where

P is the perimeter of the rectangle;

a – the length of the rectangle;

b is the width of the rectangle.

Then we get that:

2 (a + b) = 72

Also, from the condition, we know that the width is three times less than the length. That is:

a = 3b

Thus, we get a system of equations:

2 (a + b) = 72

a = 3b

Substitute the second equation into the first:

2 (3b + b) = 72

b (3 + 1) = 72/2

4b = 36

b = 9 centimeters

Then the length is:

a = 3b = 3 * 9 = 27