The pilot on a jet plane flew 45 km in 2.5 minutes what was the speed of the plane.

univerkov | July 22, 2021 | education

These tasks: S (the distance that the pilot flew in a jet plane) = 45 km (45 * 10 ^ 3 m); t (flight duration) = 2.5 min (150 s).

The speed of a jet plane is determined by the formula: V = S / t = 45 * 10 ^ 3/150 = 300 m / s (1080 km / h).

Answer: The speed of the jet plane was 300 m / s or 1080 km / h.

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