The plane, accelerating before takeoff, moved uniformly accelerated for a certain period of time. What was the acceleration of the aircraft in this case, if in 30 s its speed increased from 10 to 55 m / s?
These tasks: t (time interval during which the considered aircraft moved uniformly accelerated) = 30 s; V0 (initial speed) = 10 m / s; V (aircraft speed after acceleration) = 55 m / s.
The acceleration of the considered aircraft before takeoff is determined by the formula: a = (V – V0) / t.
Let’s calculate: a = (55 – 10) / 30 = 1.5 m / s2.
Answer: During acceleration, the aircraft in question moved with an acceleration of 1.5 m / s2.
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