The probability of successful delivery of the laboratory work for each of 2 students is 0.5. Students take the laboratory work in turn, each with two attempts. Find the probability that at least one student will pass the laboratory work.
The probability that the student will pass the laboratory work is p = 0.5.
The probability that he will not pass q = 1 – p = 1 – 0.5 = 0.5.
The likelihood that no student will turn in a job.
P4 (0) = q ^ 4 = 0.5 ^ 4 = 0.0625;
The probability of an opposite event such that at least one student will pass the laboratory work:
P4 (1) = 1 – P4 (0) = 1 – 0.0625 = 0.9375.
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