The probability that the TV will require repair during the warranty period is 0.2.

The probability that the TV will require repair during the warranty period is 0.2. What is the likelihood that during the warranty period, out of 6 TVs, 2 TVs will need to be repaired.

The probability that the TV set will require repair: p = 0.2;
The probability that the TV will not require repair: q = 1 – p = 1 – 0.2 = 0.8;
The probability that out of 6 TVs 2 TVs will need to be repaired according to the Bernoulli formula:
P6 (2) = C (6.2) p ^ 2 q ^ 4 = (5 6/2) 0.2 ^ 2 0.8 ^ 4 = 0.246;
Answer: 0.246.