If we cut the ball with a certain plane through the center, then we get a circle in the section. Since the points in the ball are equidistant from the center, this circle will everywhere have the same cross-section (when passing through the center).
Consequently, the cross-sectional area will be equal to the area of the circle.
S = π x R²
π = 3.14 …
S = 3.14 x 6²
S = 113.04 cm²
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