# The reaction of 10.7 g of ammonium chloride with calcium hydroxide yielded 4 L of NH3. Calculate the volume

**The reaction of 10.7 g of ammonium chloride with calcium hydroxide yielded 4 L of NH3. Calculate the volume fraction of the output of ammonia in% of the theoretical.**

The reaction of ammonium with calcium hydroxide is described by the following chemical reaction equation:

2NH4Cl + Ca (OH) 2 = 2NH3 + CaCl2 + 2H2O;

Two moles of ammonium chloride react with one mole of calcium hydroxide.

Determine the amount of substance in 10.7 grams of ammonium chloride.

M NH4Cl = 14 + 4 + 35.5 = 53.5 grams / mol;

N NH4Cl = 10.7 / 53.5 = 0.2 mol;

0.2 mol of ammonium chloride will react to form 0.2 mol of ammonia.

Let’s find the theoretical volume of ammonia:

Under normal conditions, one mole of ideal gas takes up a volume of 22.4 liters.

V NH3 = 0.2 x 22.4 = 4.48 liters;

The product yield will be equal to the ratio of practical and theoretical volume and will be:

K = 4.00 / 4.48 = 0.8928 = 89.28%;