The reaction of 30 g of acetic acid with ethanol gave 28.6 g of ethyl acetate. dilate the yield of the reaction product.

1. Let’s write down the solution:
m = 30 g. m = 28.6 g; W -?
CH3COOH + C2H5OH = CH3COO – C2H5 + H2 – esterification, ethyl acetate was obtained;
2. We make calculations by the formulas:
M (CH3COOH) = 60 g / mol.
M (ether) = 88 g / mol.
3. Determine the amount of the original substance:
Y (CH3COOH) = m / M = 30/60 = 0.5 mol.
Y (ether) = 0.5 mol since the amount of substances according to the equation is 1 mol.
4. Let’s calculate the mass and yield of the product:
m (ether) = Y * M = 0.5 * 88 = 44 g (theoretical mass).
W = 28.6 / 44 * 100 = 65%
Answer: the mass of ethyl acetate is 44 g, the yield is 65%.



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