The right shoulder of a balanced weightless lever has a length of 25 cm. A weight weighing 6 N is suspended from it.

The right shoulder of a balanced weightless lever has a length of 25 cm. A weight weighing 6 N is suspended from it. Find the length of the left shoulder if a weight of 10 N is suspended from it?

Lp = 25 cm = 0.25 m.

Fп = 6 N.

Fl = 10 N.

Ll -?

When the weightless lever is in equilibrium, the moments of forces that act on the right Mп and left sides Ml of the lever are the same: Mp = Ml.

The moment of force M is the product of the force F to the smallest distance from the line of its action to the axis of balance L, which is called the shoulder: M = F * L.

Fp * Lp = Fl * Ll.

Let us express the length of the left shoulder Ll by the formula: Ll = Fp * Lp / Fl.

Ll = 6 N * 0.25 m / 10 N = 0.15 m.

Answer: the length of the left shoulder is Ll = 0.15 m.

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