The scuba diver plunged into the water to a depth of 25 m. With what force does the water press on the scuba diver’s chest? What is the air pressure in a scuba diver’s lungs?
h = 25 m.
ρ = 1000 kg / m ^ 3.
g = 9.8 m / s ^ 2.
R – ?
The hydrostatic pressure of the liquid is determined by the formula: P = ρ * g * h. Where ρ is the density of the liquid, g is the acceleration of gravity, h is the height of the liquid, in our case the depth of the scuba diver’s immersion.
P = 1000 kg / m ^ 3 * 9.8 m / s ^ 2 * 25 m = 245000 Pa.
Answer: pressure in the scuba diver’s lungs is P = 245000 Pa.
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