# The side of the rectangle is 12 cm and 20 cm how many times will its area

**The side of the rectangle is 12 cm and 20 cm how many times will its area and perimeter increase if the length of each side is increased by 25%?**

1. The length of the rectangle is 20 cm, the width is 12 cm.

Find the perimeter of the rectangle.

P1 = (20 + 12) * 2 = 32 * 2 = 64 cm.

Find the area of the rectangle.

S1 = 20 * 12 = 240 sq. Cm.

2. The length and width are increased by 25%.

25% = 25/100 values.

The length began to be 20 + 20 * 25/100 = 20 + 5 = 25 cm.

The width began to be 12 + 12 * 25/100 = 12 + 3 = 15 cm.

3. Find the perimeter of the new rectangle.

P2 = (25 + 15) * 2 = 40 * 2 = 80 cm.

Find the area of the rectangle.

S2 = 25 * 15 = 375 sq. Cm.

4.P2 / P1 = 80/64 = 1.25 times

S2 / S1 = 375/240 = 25/16 = 1.5625 times.

Answer: The perimeter will increase by 1.25 times; the area will increase 1.5625 times.