The side of the rectangle is 12 cm and 20 cm how many times will its area
The side of the rectangle is 12 cm and 20 cm how many times will its area and perimeter increase if the length of each side is increased by 25%?
1. The length of the rectangle is 20 cm, the width is 12 cm.
Find the perimeter of the rectangle.
P1 = (20 + 12) * 2 = 32 * 2 = 64 cm.
Find the area of the rectangle.
S1 = 20 * 12 = 240 sq. Cm.
2. The length and width are increased by 25%.
25% = 25/100 values.
The length began to be 20 + 20 * 25/100 = 20 + 5 = 25 cm.
The width began to be 12 + 12 * 25/100 = 12 + 3 = 15 cm.
3. Find the perimeter of the new rectangle.
P2 = (25 + 15) * 2 = 40 * 2 = 80 cm.
Find the area of the rectangle.
S2 = 25 * 15 = 375 sq. Cm.
4.P2 / P1 = 80/64 = 1.25 times
S2 / S1 = 375/240 = 25/16 = 1.5625 times.
Answer: The perimeter will increase by 1.25 times; the area will increase 1.5625 times.
