# The sides of the rectangle are 6 cm and 4 cm. How much is its area less than the area of a square whose

**The sides of the rectangle are 6 cm and 4 cm. How much is its area less than the area of a square whose perimeter is equal to the perimeter of this rectangle?**

1) Calculate the area of the rectangle by multiplying its length and width:

6 * 4 = 24 cm ^ 2.

2) Find the perimeter of the rectangle as the sum of the lengths of all its four sides:

6 + 6 + 4 + 4 = 20 cm.

3) By the condition of the problem, the perimeter of the square is equal to the perimeter of the rectangle, which means that it is also equal to 20 cm.

4) All sides of a square are equal. Let’s determine the length of the side of the square:

20: 4 = 5 cm.

5) Find the area of the square:

5 * 5 = 25 cm ^ 2.

6) Find out how much the area of the rectangle is less than the area of the square:

25 – 24 = 1 cm ^ 2.

Answer: 1 cm ^ 2.