The skier went down the hill in 6 seconds, moving with a constant acceleration of 0.4 m / s². Determine the length of the slide if it is known that at the beginning of the descent the speed of the skier was 5 m / s.
t = 6 s – the time of the skier’s movement;
a = 0.4 m / s ^ 2 – skier’s acceleration;
V0 = 5 m / s – the initial speed of the skier.
It is required to find the length of the slide S.
S = V0 * t + a * t ^ 2/2 = 5 * 6 + 0.4 * 6 * 6/2 = 30 + 7.2 = 37.2 meters.
Answer: the length of the slide is 37.2 meters.
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