The student traveled half of the way on a bicycle at speed v1 = 16 km / h, then half of the remaining time he rode

| September 29, 2021 | education

The student traveled half of the way on a bicycle at speed v1 = 16 km / h, then half of the remaining time he rode at speed v2 = 12 km / h, and then walked to the end of the path at speed. v3 = 5km / h. Determine the student’s average speed.

To find the average speed of the student in question, we will use the formula: V = S / t = S / (t1 + t2 + t3) = S / (t1 + 2t2) = S / (S1 / V1 + 2 * S2 / (V2 + V3 )) = S / (S / 2V1 + S / (V2 + V3)) = 1 / (1 / 2V1 + 1 / (V2 + V3)).

The values of the variables: V1 – the first speed on the bike (V1 = 16 km / h); V2 – the second speed on the bike (V2 = 12 km / h); V3 – walking speed (V3 = 5 km / h).

Let’s calculate: V = 1 / (1 / 2V1 + 1 / (V2 + V3)) = 1 / (1 / (2 * 16) + 1 / (12 + 5)) = 11.1 km / h.

Answer: The student in question was moving at an average speed of 11.1 km / h.



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