# The temperature of the heater of an ideal heat engine is 127 ºС, the temperature of the refrigerator is 27 ºС.

The temperature of the heater of an ideal heat engine is 127 ºС, the temperature of the refrigerator is 27 ºС. The working body of the machine receives 3 MJ of heat from the heater every second. Determine the power of the machine.

To determine the power of the indicated ideal heat engine, we use the formula: N = A / t = (Qn – Qx) / t = (Qn – Qn * (1 – η)) / t = (Qn – Qn * (1 – (1 – Tx / Тн))) / t = (Qн – Qн * Тх / Тн) / t.

Variables: Тн (machine heater temperature) = 127 ºС (400 К); Тх (refrigerator temperature) = 27 ºС (300 К); Qн (heat from the heater) = 3 MJ (3 * 10 ^ 6 J); t (cycle time) = 1 s.

Calculation: N = (Qn – Qn * Tx / Tn) / t = (3 * 10 ^ 6 – 3 * 10 ^ 6 * 300/400) / 1 = 750 * 10 ^ 3 W = 750 kW.

Answer: The power of the specified heat engine is 750 kW.

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