The thermochemical equation for the reaction of complete combustion of acetylene: 2C2H2 + 5O2 = 4CO2 + 2H2O + 2610 kJ how much heat is released when using 1.12 liters of acetylene?
V (C2H2) = 1.12 L
Vm = 22.4 l / mol
1) Write down the thermochemical equation of the reaction:
2C2H2 + 5O2 => 4CO2 + 2H2O + 2610 kJ;
2) Calculate the amount of acetylene substance:
n (C2H2) = V (C2H2) / Vm = 1.12 / 22.4 = 0.05 mol;
3) Make a proportion and calculate the amount of heat that was released during this reaction:
2 mol of acetylene – 2610 kJ;
0.05 mol of acetylene – Q1 kJ;
Q1 = 0.05 * 2610/2 = 65.25 kJ.
Answer: During the reaction, 65.25 kJ of heat was released.
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