# The total energy of electromagnetic oscillations in an ideal oscillatory circuit is 0.2 mJ

**The total energy of electromagnetic oscillations in an ideal oscillatory circuit is 0.2 mJ, the maximum voltage is 100V, the amplitude of the current is 1A. determine the inductance and electrical capacity of the circuit**

An ideal oscillating circuit includes an inductor and a capacitor, but there is no loss resistance. The energy of such a circuit is determined by the formula: W = L * I ^ 2 max / 2 (the energy is accumulated in the magnetic field of the coil), or W = C * U ^ 2 max / 2 (the energy of the electric field is accumulated by the capacitor).

L is the inductance of the coil, I is the alternating current, U is the voltage, C is the electrical capacity of the circuit.

L = 2 * W / I ^ 2 max = 2 * 0.2 * 10 ^ -3 / 12 = 0.4 * 10 ^ -3 H.

С = 2 * W / U2 max = 2 * 0, 2 * 10 ^ -3 / 100 ^ 2 = 0.4 * 10 ^ -3 / 10000 = 0.4 * 10 ^ -7 F.

Answer: the inductance of the circuit is 0.4 * 10 ^ -3 H, the electrical capacity of the circuit is 0.4 * 10 ^ -7 F.